.-3x^2+14x-8=0

Solution for .-3x^2+14x-8=0 equation:

.-3x^2+14x-8=0

We add all the numbers together, and all the variables

-3x^2+14x=0

a = -3; b = 14; c = 0;
Δ = b2-4ac
Δ = 142-4·(-3)·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-14}{2*-3}=\frac{-28}{-6}
=4+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+14}{2*-3}=\frac{0}{-6}
=0
$